What are the solutions to the equation 4x^2-20x=-25 ?

The solutions to the equation 4x^2-20x=-25 are x= 5/2

Find the zeros of 4x^2-20x=-25

The zeros of 4x^2-20x=-25 are x= 5/2

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4 x^{2} - 20 x = - 25

x = \frac{5}{2}

Decimal Notation

x = 2.5

Solution steps

4 x^{2} - 20 x = - 25

Move

25

to the left side

4 x^{2} - 20 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 20 )}{2 \cdot 4}

\frac{- ( - 20 )}{2 \cdot 4} = \frac{5}{2}

x = \frac{5}{2}

The solution to the quadratic equation is:

x = \frac{5}{2}

3 x^{2} - 20 x + 20 = 0

a^{2} + 2^{2} = 5^{2}

x (x + 1) = 240

a, 5 a^{2} + 5 b^{2} = 2 a - 6 b - 2

x (x + 1) = 210

What are the solutions to the equation 4x^2-20x=-25 ?
The solutions to the equation 4x^2-20x=-25 are x= 5/2
Find the zeros of 4x^2-20x=-25
The zeros of 4x^2-20x=-25 are x= 5/2