What are the solutions to the equation a^2+2^2=5^2 ?

The solutions to the equation a^2+2^2=5^2 are a=sqrt(21),a=-sqrt(21)

Find the zeros of a^2+2^2=5^2

The zeros of a^2+2^2=5^2 are a=sqrt(21),a=-sqrt(21)

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a^{2} + 2^{2} = 5^{2}

a = 21, a = - 21

Decimal Notation

a = 4.58257 \dots, a = - 4.58257 \dots

Solution steps

a^{2} + 2^{2} = 5^{2}

Move

2^{2}

to the right side

a^{2} = 21

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 21, a = - 21

x (x + 1) = 240

a, 5 a^{2} + 5 b^{2} = 2 a - 6 b - 2

x (x + 1) = 210

4 x^{2} - 6 x + 4 = 0

- \frac{1}{2} x^{2} - 24 = 0

What are the solutions to the equation a^2+2^2=5^2 ?
The solutions to the equation a^2+2^2=5^2 are a=sqrt(21),a=-sqrt(21)
Find the zeros of a^2+2^2=5^2
The zeros of a^2+2^2=5^2 are a=sqrt(21),a=-sqrt(21)