What are the solutions to the equation x(x+1)=210 ?

The solutions to the equation x(x+1)=210 are x=14,x=-15

Find the zeros of x(x+1)=210

The zeros of x(x+1)=210 are x=14,x=-15

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x (x + 1) = 210

x = 14, x = - 15

Solution steps

x (x + 1) = 210

Expand

x (x + 1) : x^{2} + x

x^{2} + x = 210

Move

210

to the left side

x^{2} + x - 210 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 210 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 210) = 29

x_{1, 2} = \frac{- 1 \pm 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 29}{2 \cdot 1}, x_{2} = \frac{- 1 - 29}{2 \cdot 1}

x = \frac{- 1 + 29}{2 \cdot 1} : 14

x = \frac{- 1 - 29}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 14, x = - 15

4 x^{2} - 6 x + 4 = 0

- \frac{1}{2} x^{2} - 24 = 0

x^{2} + 4 x + 2 = 0

- 3 x^{2} - 4 x + 3 = 0

24 x^{2} + 8 x = 0

What are the solutions to the equation x(x+1)=210 ?
The solutions to the equation x(x+1)=210 are x=14,x=-15
Find the zeros of x(x+1)=210
The zeros of x(x+1)=210 are x=14,x=-15