What are the solutions to the equation solvefor a,a^2=2ax-x^2 ?

The solutions to the equation solvefor a,a^2=2ax-x^2 are a=x

Find the zeros of solvefor a,a^2=2ax-x^2

The zeros of solvefor a,a^2=2ax-x^2 are a=x

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solve for

a, a^{2} = 2 a x - x^{2}

a = x

Solution steps

a^{2} = 2 a x - x^{2}

Move

x^{2}

to the left side

a^{2} + x^{2} = 2 a x

Move

2 a x

to the left side

a^{2} + x^{2} - 2 a x = 0

Write in the standard form

a x^{2} + b x + c = 0

a^{2} - 2 x a + x^{2} = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 2 x ) \pm ( - 2 x ) ^{2} - 4 \cdot 1 \cdot x ^{2}}{2 \cdot 1}

(- 2 x)^{2} - 4 \cdot 1 \cdot x^{2} = 0

a_{1, 2} = \frac{- ( - 2 x ) \pm 0}{2 \cdot 1}

a = \frac{- ( - 2 x )}{2 \cdot 1}

Simplify

\frac{- ( - 2 x )}{2 \cdot 1} : x

a = x

The solution to the quadratic equation is:

a = x

- 5 x^{2} - 114 = 50 x - 9

t, (1 - t^{2}) x^{2} - 2 t^{2} x - (t^{2} + 1) = 0

- 4 x^{2} - 530 x + 265 = 0

10 x^{2} + 12 x + 2 = 0

6 x^{2} - 42 x + 36 = 0

What are the solutions to the equation solvefor a,a^2=2ax-x^2 ?
The solutions to the equation solvefor a,a^2=2ax-x^2 are a=x
Find the zeros of solvefor a,a^2=2ax-x^2
The zeros of solvefor a,a^2=2ax-x^2 are a=x