What are the solutions to the equation 2x(x-3)+5(x-3)=0 ?

The solutions to the equation 2x(x-3)+5(x-3)=0 are x=3,x=-5/2

Find the zeros of 2x(x-3)+5(x-3)=0

The zeros of 2x(x-3)+5(x-3)=0 are x=3,x=-5/2

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2 x (x - 3) + 5 (x - 3) = 0

x = 3, x = - \frac{5}{2}

Decimal Notation

x = 3, x = - 2.5

Solution steps

2 x (x - 3) + 5 (x - 3) = 0

Expand

2 x (x - 3) + 5 (x - 3) : 2 x^{2} - x - 15

2 x^{2} - x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 15) = 11

x_{1, 2} = \frac{- ( - 1 ) \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 11}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 11}{2 \cdot 2}

x = \frac{- ( - 1 ) + 11}{2 \cdot 2} : 3

x = \frac{- ( - 1 ) - 11}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 3, x = - \frac{5}{2}

x^{2} - 12 x - 20 = 0

2 x + 3 - x^{2} = 0

x, x^{2} y - x y^{2} + y^{2} = 7

m x^{2} + (2 m - 1) x + m - 1 = 0

y, x = y^{2} - 4 y + 1

What are the solutions to the equation 2x(x-3)+5(x-3)=0 ?
The solutions to the equation 2x(x-3)+5(x-3)=0 are x=3,x=-5/2
Find the zeros of 2x(x-3)+5(x-3)=0
The zeros of 2x(x-3)+5(x-3)=0 are x=3,x=-5/2