What are the solutions to the equation c^2+5c=7c+16 ?

The solutions to the equation c^2+5c=7c+16 are c=1+sqrt(17),c=1-sqrt(17)

Find the zeros of c^2+5c=7c+16

The zeros of c^2+5c=7c+16 are c=1+sqrt(17),c=1-sqrt(17)

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c^{2} + 5 c = 7 c + 16

c = 1 + 17, c = 1 - 17

Decimal Notation

c = 5.12310 \dots, c = - 3.12310 \dots

Solution steps

c^{2} + 5 c = 7 c + 16

Move

16

to the left side

c^{2} + 5 c - 16 = 7 c

Move

7 c

to the left side

c^{2} - 2 c - 16 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 16) = 217

c_{1, 2} = \frac{- ( - 2 ) \pm 2 17}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 2 ) + 2 17}{2 \cdot 1}, c_{2} = \frac{- ( - 2 ) - 2 17}{2 \cdot 1}

c = \frac{- ( - 2 ) + 2 17}{2 \cdot 1} : 1 + 17

c = \frac{- ( - 2 ) - 2 17}{2 \cdot 1} : 1 - 17

The solutions to the quadratic equation are:

c = 1 + 17, c = 1 - 17

u^{2} - 2 u

(4 x + 5)^{2} = 9

6 x^{2} + 10 x = 0

- 1 - 3 a^{2} = - 4

4 (t + 1)^{2} = 9

What are the solutions to the equation c^2+5c=7c+16 ?
The solutions to the equation c^2+5c=7c+16 are c=1+sqrt(17),c=1-sqrt(17)
Find the zeros of c^2+5c=7c+16
The zeros of c^2+5c=7c+16 are c=1+sqrt(17),c=1-sqrt(17)