What are the solutions to the equation 8x(x+2)-8=2x(2+x)+9 ?

The solutions to the equation 8x(x+2)-8=2x(2+x)+9 are x=(-6+sqrt(138))/6 ,x=-(6+sqrt(138))/6

Find the zeros of 8x(x+2)-8=2x(2+x)+9

The zeros of 8x(x+2)-8=2x(2+x)+9 are x=(-6+sqrt(138))/6 ,x=-(6+sqrt(138))/6

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8 x (x + 2) - 8 = 2 x (2 + x) + 9

x = \frac{- 6 + 138}{6}, x = - \frac{6 + 138}{6}

Decimal Notation

x = 0.95789 \dots, x = - 2.95789 \dots

Solution steps

8 x (x + 2) - 8 = 2 x (2 + x) + 9

Expand

8 x (x + 2) - 8 : 8 x^{2} + 16 x - 8

Expand

2 x (2 + x) + 9 : 4 x + 2 x^{2} + 9

8 x^{2} + 16 x - 8 = 4 x + 2 x^{2} + 9

Move

9

to the left side

8 x^{2} + 16 x - 17 = 4 x + 2 x^{2}

Move

2 x^{2}

to the left side

6 x^{2} + 16 x - 17 = 4 x

Move

4 x

to the left side

6 x^{2} + 12 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 6 ( - 17 )}{2 \cdot 6}

1 2^{2} - 4 \cdot 6 (- 17) = 2138

x_{1, 2} = \frac{- 12 \pm 2 138}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 12 + 2 138}{2 \cdot 6}, x_{2} = \frac{- 12 - 2 138}{2 \cdot 6}

x = \frac{- 12 + 2 138}{2 \cdot 6} : \frac{- 6 + 138}{6}

x = \frac{- 12 - 2 138}{2 \cdot 6} : - \frac{6 + 138}{6}

The solutions to the quadratic equation are:

x = \frac{- 6 + 138}{6}, x = - \frac{6 + 138}{6}

x^{2} + 8 x + 14 = 0

x^{2} - 16 x + 63 = 0

2 x^{2} - 20 = 6 x

3 x^{2} - x + 10 = 0

j (x) = (x - 3)^{2} - 4

What are the solutions to the equation 8x(x+2)-8=2x(2+x)+9 ?
The solutions to the equation 8x(x+2)-8=2x(2+x)+9 are x=(-6+sqrt(138))/6 ,x=-(6+sqrt(138))/6
Find the zeros of 8x(x+2)-8=2x(2+x)+9
The zeros of 8x(x+2)-8=2x(2+x)+9 are x=(-6+sqrt(138))/6 ,x=-(6+sqrt(138))/6