What are the solutions to the equation -x^2+10x=16 ?

The solutions to the equation -x^2+10x=16 are x=2,x=8

Find the zeros of -x^2+10x=16

The zeros of -x^2+10x=16 are x=2,x=8

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- x^{2} + 10 x = 16

x = 2, x = 8

Solution steps

- x^{2} + 10 x = 16

Move

16

to the left side

- x^{2} + 10 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) ( - 16 )}{2 ( - 1 )}

1 0^{2} - 4 (- 1) (- 16) = 6

x_{1, 2} = \frac{- 10 \pm 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 10 + 6}{2 ( - 1 )}, x_{2} = \frac{- 10 - 6}{2 ( - 1 )}

x = \frac{- 10 + 6}{2 ( - 1 )} : 2

x = \frac{- 10 - 6}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

x = 2, x = 8

4 x^{2} + 2 x - 12 = 0

y^{2} + y

x, x^{2} - 4 x = 0

x^{2} + 15 x - 100 = 0

- x^{2} + 500 x - 62.5 = 0

What are the solutions to the equation -x^2+10x=16 ?
The solutions to the equation -x^2+10x=16 are x=2,x=8
Find the zeros of -x^2+10x=16
The zeros of -x^2+10x=16 are x=2,x=8