What are the solutions to the equation solvefor x,x^2-4x=0 ?

The solutions to the equation solvefor x,x^2-4x=0 are x=4,x=0

Find the zeros of solvefor x,x^2-4x=0

The zeros of solvefor x,x^2-4x=0 are x=4,x=0

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x, x^{2} - 4 x = 0

x = 4, x = 0

Solution steps

x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

x = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 4, x = 0

x^{2} + 15 x - 100 = 0

- x^{2} + 500 x - 62.5 = 0

9 x^{2} - 12 x + 4 = 0

x^{2} + 6 x + 17 = 0

x^{2} - 4 x = 8

What are the solutions to the equation solvefor x,x^2-4x=0 ?
The solutions to the equation solvefor x,x^2-4x=0 are x=4,x=0
Find the zeros of solvefor x,x^2-4x=0
The zeros of solvefor x,x^2-4x=0 are x=4,x=0