What are the solutions to the equation x^2+6x+17=0 ?

The solutions to the equation x^2+6x+17=0 are x=-3+2sqrt(2)i,x=-3-2sqrt(2)i

Find the zeros of x^2+6x+17=0

The zeros of x^2+6x+17=0 are x=-3+2sqrt(2)i,x=-3-2sqrt(2)i

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x^{2} + 6 x + 17 = 0

x = - 3 + 22 i, x = - 3 - 22 i

Solution steps

x^{2} + 6 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 17 : 42 i

x_{1, 2} = \frac{- 6 \pm 4 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4 2 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 4 2 i}{2 \cdot 1}

x = \frac{- 6 + 4 2 i}{2 \cdot 1} : - 3 + 22 i

x = \frac{- 6 - 4 2 i}{2 \cdot 1} : - 3 - 22 i

The solutions to the quadratic equation are:

x = - 3 + 22 i, x = - 3 - 22 i

x^{2} - 4 x = 8

16 x^{2} + 36 x + 8 = 0

x^{2} - 2 x - 8 = 0

2 a^{2} = 72

0 = x^{2} + 2 x + 2

What are the solutions to the equation x^2+6x+17=0 ?
The solutions to the equation x^2+6x+17=0 are x=-3+2sqrt(2)i,x=-3-2sqrt(2)i
Find the zeros of x^2+6x+17=0
The zeros of x^2+6x+17=0 are x=-3+2sqrt(2)i,x=-3-2sqrt(2)i