What are the solutions to the equation -3x^2-8x+16=0 ?

The solutions to the equation -3x^2-8x+16=0 are x=-4,x= 4/3

Find the zeros of -3x^2-8x+16=0

The zeros of -3x^2-8x+16=0 are x=-4,x= 4/3

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- 3 x^{2} - 8 x + 16 = 0

x = - 4, x = \frac{4}{3}

Decimal Notation

x = - 4, x = 1.33333 \dots

Solution steps

- 3 x^{2} - 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 3 ) \cdot 16}{2 ( - 3 )}

(- 8)^{2} - 4 (- 3) \cdot 16 = 16

x_{1, 2} = \frac{- ( - 8 ) \pm 16}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 16}{2 ( - 3 )}, x_{2} = \frac{- ( - 8 ) - 16}{2 ( - 3 )}

x = \frac{- ( - 8 ) + 16}{2 ( - 3 )} : - 4

x = \frac{- ( - 8 ) - 16}{2 ( - 3 )} : \frac{4}{3}

The solutions to the quadratic equation are:

x = - 4, x = \frac{4}{3}

x^{2} + 2 x - 15 = 0

k^{2} = 6 k - 10

x, 16 y^{2} - x^{2} + 2 x + 64 y + 63 = 0

(x - 7) (x + 3) = 0

5 X^{2} + 7 X + 2 = 0

What are the solutions to the equation -3x^2-8x+16=0 ?
The solutions to the equation -3x^2-8x+16=0 are x=-4,x= 4/3
Find the zeros of -3x^2-8x+16=0
The zeros of -3x^2-8x+16=0 are x=-4,x= 4/3