What are the solutions to the equation 9x^2-72x=0 ?

The solutions to the equation 9x^2-72x=0 are x=8,x=0

Find the zeros of 9x^2-72x=0

The zeros of 9x^2-72x=0 are x=8,x=0

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9 x^{2} - 72 x = 0

x = 8, x = 0

Solution steps

9 x^{2} - 72 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 72 ) \pm ( - 72 ) ^{2} - 4 \cdot 9 \cdot 0}{2 \cdot 9}

(- 72)^{2} - 4 \cdot 9 \cdot 0 = 72

x_{1, 2} = \frac{- ( - 72 ) \pm 72}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 72 ) + 72}{2 \cdot 9}, x_{2} = \frac{- ( - 72 ) - 72}{2 \cdot 9}

x = \frac{- ( - 72 ) + 72}{2 \cdot 9} : 8

x = \frac{- ( - 72 ) - 72}{2 \cdot 9} : 0

The solutions to the quadratic equation are:

x = 8, x = 0

x^{2} - \frac{6}{7} x + 2

x, x^{2} - 2 x y + 3 y^{2} = 4

y^{2} - 2 y = 15

x^{2} + 4 x - 21 = 0

0 = (x - 2) (x + 4)

What are the solutions to the equation 9x^2-72x=0 ?
The solutions to the equation 9x^2-72x=0 are x=8,x=0
Find the zeros of 9x^2-72x=0
The zeros of 9x^2-72x=0 are x=8,x=0