What are the solutions to the equation (2x+3)(x-5)=0 ?

The solutions to the equation (2x+3)(x-5)=0 are x=-3/2 ,x=5

Find the zeros of (2x+3)(x-5)=0

The zeros of (2x+3)(x-5)=0 are x=-3/2 ,x=5

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(2 x + 3) (x - 5) = 0

x = - \frac{3}{2}, x = 5

Decimal Notation

x = - 1.5, x = 5

Solution steps

(2 x + 3) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 3 = 0 or x - 5 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x - 5 = 0 : x = 5

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 5

m^{2} - 6 m + 5 = 0

x^{2} - 2 x - 960 = 0

0 = x^{2} + 5 x + 4

- x^{2} + 2 x

- x^{2} + 6 x

What are the solutions to the equation (2x+3)(x-5)=0 ?
The solutions to the equation (2x+3)(x-5)=0 are x=-3/2 ,x=5
Find the zeros of (2x+3)(x-5)=0
The zeros of (2x+3)(x-5)=0 are x=-3/2 ,x=5