What are the solutions to the equation 0=x^2+5x+4 ?

The solutions to the equation 0=x^2+5x+4 are x=-1,x=-4

Find the zeros of 0=x^2+5x+4

The zeros of 0=x^2+5x+4 are x=-1,x=-4

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0 = x^{2} + 5 x + 4

x = - 1, x = - 4

Solution steps

0 = x^{2} + 5 x + 4

Switch sides

x^{2} + 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 4 = 3

x_{1, 2} = \frac{- 5 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 3}{2 \cdot 1}, x_{2} = \frac{- 5 - 3}{2 \cdot 1}

x = \frac{- 5 + 3}{2 \cdot 1} : - 1

x = \frac{- 5 - 3}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 1, x = - 4

- x^{2} + 2 x

- x^{2} + 6 x

5 x^{2} - 6 x - 1 = - 3 x^{2}

2 x^{2} - 13 = 53

3 x^{2} - 8 x + 9 = 0

What are the solutions to the equation 0=x^2+5x+4 ?
The solutions to the equation 0=x^2+5x+4 are x=-1,x=-4
Find the zeros of 0=x^2+5x+4
The zeros of 0=x^2+5x+4 are x=-1,x=-4