What are the solutions to the equation 5x^2-6x-1=-3x^2 ?

The solutions to the equation 5x^2-6x-1=-3x^2 are x=(3+sqrt(17))/8 ,x=(3-sqrt(17))/8

Find the zeros of 5x^2-6x-1=-3x^2

The zeros of 5x^2-6x-1=-3x^2 are x=(3+sqrt(17))/8 ,x=(3-sqrt(17))/8

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5 x^{2} - 6 x - 1 = - 3 x^{2}

x = \frac{3 + 17}{8}, x = \frac{3 - 17}{8}

Decimal Notation

x = 0.89038 \dots, x = - 0.14038 \dots

Solution steps

5 x^{2} - 6 x - 1 = - 3 x^{2}

Move

3 x^{2}

to the left side

8 x^{2} - 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 8 ( - 1 )}{2 \cdot 8}

(- 6)^{2} - 4 \cdot 8 (- 1) = 217

x_{1, 2} = \frac{- ( - 6 ) \pm 2 17}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 17}{2 \cdot 8}, x_{2} = \frac{- ( - 6 ) - 2 17}{2 \cdot 8}

x = \frac{- ( - 6 ) + 2 17}{2 \cdot 8} : \frac{3 + 17}{8}

x = \frac{- ( - 6 ) - 2 17}{2 \cdot 8} : \frac{3 - 17}{8}

The solutions to the quadratic equation are:

x = \frac{3 + 17}{8}, x = \frac{3 - 17}{8}

2 x^{2} - 13 = 53

3 x^{2} - 8 x + 9 = 0

x^{2} + 12 x = - 4

- x^{2} + 12 x - 14 = 4 x

x, x^{2} + y^{2} + (z - 1)^{2} = 1

What are the solutions to the equation 5x^2-6x-1=-3x^2 ?
The solutions to the equation 5x^2-6x-1=-3x^2 are x=(3+sqrt(17))/8 ,x=(3-sqrt(17))/8
Find the zeros of 5x^2-6x-1=-3x^2
The zeros of 5x^2-6x-1=-3x^2 are x=(3+sqrt(17))/8 ,x=(3-sqrt(17))/8