What are the solutions to the equation -x^2+12x-14=4x ?

The solutions to the equation -x^2+12x-14=4x are x=4-sqrt(2),x=4+sqrt(2)

Find the zeros of -x^2+12x-14=4x

The zeros of -x^2+12x-14=4x are x=4-sqrt(2),x=4+sqrt(2)

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- x^{2} + 12 x - 14 = 4 x

x = 4 - 2, x = 4 + 2

Decimal Notation

x = 2.58578 \dots, x = 5.41421 \dots

Solution steps

- x^{2} + 12 x - 14 = 4 x

Move

4 x

to the left side

- x^{2} + 8 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) ( - 14 )}{2 ( - 1 )}

8^{2} - 4 (- 1) (- 14) = 22

x_{1, 2} = \frac{- 8 \pm 2 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 2}{2 ( - 1 )}, x_{2} = \frac{- 8 - 2 2}{2 ( - 1 )}

x = \frac{- 8 + 2 2}{2 ( - 1 )} : 4 - 2

x = \frac{- 8 - 2 2}{2 ( - 1 )} : 4 + 2

The solutions to the quadratic equation are:

x = 4 - 2, x = 4 + 2

x, x^{2} + y^{2} + (z - 1)^{2} = 1

3 (x + 1)^{2} = 0

x, 2 x^{2} - 4 x y + 8 y^{2} + 7 = 0

2 p^{2} - 6 p - 58 = 0

9 x^{2} + 24 x = 0

What are the solutions to the equation -x^2+12x-14=4x ?
The solutions to the equation -x^2+12x-14=4x are x=4-sqrt(2),x=4+sqrt(2)
Find the zeros of -x^2+12x-14=4x
The zeros of -x^2+12x-14=4x are x=4-sqrt(2),x=4+sqrt(2)