What are the solutions to the equation 2p^2-6p-58=0 ?

The solutions to the equation 2p^2-6p-58=0 are p=(3+5sqrt(5))/2 ,p=(3-5sqrt(5))/2

Find the zeros of 2p^2-6p-58=0

The zeros of 2p^2-6p-58=0 are p=(3+5sqrt(5))/2 ,p=(3-5sqrt(5))/2

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2 p^{2} - 6 p - 58 = 0

p = \frac{3 + 5 5}{2}, p = \frac{3 - 5 5}{2}

Decimal Notation

p = 7.09016 \dots, p = - 4.09016 \dots

Solution steps

2 p^{2} - 6 p - 58 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 ( - 58 )}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 (- 58) = 105

p_{1, 2} = \frac{- ( - 6 ) \pm 10 5}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- ( - 6 ) + 10 5}{2 \cdot 2}, p_{2} = \frac{- ( - 6 ) - 10 5}{2 \cdot 2}

p = \frac{- ( - 6 ) + 10 5}{2 \cdot 2} : \frac{3 + 5 5}{2}

p = \frac{- ( - 6 ) - 10 5}{2 \cdot 2} : \frac{3 - 5 5}{2}

The solutions to the quadratic equation are:

p = \frac{3 + 5 5}{2}, p = \frac{3 - 5 5}{2}

9 x^{2} + 24 x = 0

0.48 x^{2} + 3.4 x - 5 = 0

x = - x^{2}

(x + 4)^{2} - 4 = 36

3 p^{2} - 4 = - 6

What are the solutions to the equation 2p^2-6p-58=0 ?
The solutions to the equation 2p^2-6p-58=0 are p=(3+5sqrt(5))/2 ,p=(3-5sqrt(5))/2
Find the zeros of 2p^2-6p-58=0
The zeros of 2p^2-6p-58=0 are p=(3+5sqrt(5))/2 ,p=(3-5sqrt(5))/2