What are the solutions to the equation (x+4)^2-4=36 ?

The solutions to the equation (x+4)^2-4=36 are x=2sqrt(10)-4,x=-2sqrt(10)-4

Find the zeros of (x+4)^2-4=36

The zeros of (x+4)^2-4=36 are x=2sqrt(10)-4,x=-2sqrt(10)-4

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(x + 4)^{2} - 4 = 36

x = 210 - 4, x = - 210 - 4

Decimal Notation

x = 2.32455 \dots, x = - 10.32455 \dots

Solution steps

(x + 4)^{2} - 4 = 36

Move

4

to the right side

(x + 4)^{2} = 40

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 40 : x = 210 - 4

Solve

x + 4 = - 40 : x = - 210 - 4

The solutions to the quadratic equation are:

x = 210 - 4, x = - 210 - 4

3 p^{2} - 4 = - 6

x^{2} + 6 x + 8 = - 1

- 2 x^{2} + 8 x - 5

6 x + 6 = (4 - x) (x + 7)

x^{2} + x = 7

What are the solutions to the equation (x+4)^2-4=36 ?
The solutions to the equation (x+4)^2-4=36 are x=2sqrt(10)-4,x=-2sqrt(10)-4
Find the zeros of (x+4)^2-4=36
The zeros of (x+4)^2-4=36 are x=2sqrt(10)-4,x=-2sqrt(10)-4