What are the solutions to the equation x^2+6x+8=-1 ?

The solutions to the equation x^2+6x+8=-1 are x=-3

Find the zeros of x^2+6x+8=-1

The zeros of x^2+6x+8=-1 are x=-3

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x^{2} + 6 x + 8 = - 1

x = - 3

Solution steps

x^{2} + 6 x + 8 = - 1

Move

1

to the left side

x^{2} + 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

x = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

- 2 x^{2} + 8 x - 5

6 x + 6 = (4 - x) (x + 7)

x^{2} + x = 7

10 x^{2} + 31 x + 15 = 0

(x + 5)^{2} = 2

What are the solutions to the equation x^2+6x+8=-1 ?
The solutions to the equation x^2+6x+8=-1 are x=-3
Find the zeros of x^2+6x+8=-1
The zeros of x^2+6x+8=-1 are x=-3