What are the solutions to the equation (x+5)^2=2 ?

The solutions to the equation (x+5)^2=2 are x=sqrt(2)-5,x=-sqrt(2)-5

Find the zeros of (x+5)^2=2

The zeros of (x+5)^2=2 are x=sqrt(2)-5,x=-sqrt(2)-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 5)^{2} = 2

x = 2 - 5, x = - 2 - 5

Decimal Notation

x = - 3.58578 \dots, x = - 6.41421 \dots

Solution steps

(x + 5)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 2 : x = 2 - 5

Solve

x + 5 = - 2 : x = - 2 - 5

The solutions to the quadratic equation are:

x = 2 - 5, x = - 2 - 5

k^{2} - 16 = 0

b, A = \frac{1}{6} b^{2} c

x^{2} - 6 x + 8 = 0

y^{2} - 8 y

4 x^{2} - 4 x + 11 = 0

What are the solutions to the equation (x+5)^2=2 ?
The solutions to the equation (x+5)^2=2 are x=sqrt(2)-5,x=-sqrt(2)-5
Find the zeros of (x+5)^2=2
The zeros of (x+5)^2=2 are x=sqrt(2)-5,x=-sqrt(2)-5