What are the solutions to the equation y^2+11y+10=0 ?

The solutions to the equation y^2+11y+10=0 are y=-1,y=-10

Find the zeros of y^2+11y+10=0

The zeros of y^2+11y+10=0 are y=-1,y=-10

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y^{2} + 11 y + 10 = 0

y = - 1, y = - 10

Solution steps

y^{2} + 11 y + 10 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 10 = 9

y_{1, 2} = \frac{- 11 \pm 9}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 11 + 9}{2 \cdot 1}, y_{2} = \frac{- 11 - 9}{2 \cdot 1}

y = \frac{- 11 + 9}{2 \cdot 1} : - 1

y = \frac{- 11 - 9}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

y = - 1, y = - 10

24 x = - 48 - 3 x^{2}

x^{2} + 9^{2} = 1 0^{2}

x^{2} - 96 = 20 x

x, x^{2} + y^{2} + 10 y + 25 = 0

x^{2} - \frac{1}{3} x + 1

What are the solutions to the equation y^2+11y+10=0 ?
The solutions to the equation y^2+11y+10=0 are y=-1,y=-10
Find the zeros of y^2+11y+10=0
The zeros of y^2+11y+10=0 are y=-1,y=-10