What are the solutions to the equation (2x-9)(x+8)=0 ?

The solutions to the equation (2x-9)(x+8)=0 are x= 9/2 ,x=-8

Find the zeros of (2x-9)(x+8)=0

The zeros of (2x-9)(x+8)=0 are x= 9/2 ,x=-8

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(2 x - 9) (x + 8) = 0

x = \frac{9}{2}, x = - 8

Decimal Notation

x = 4.5, x = - 8

Solution steps

(2 x - 9) (x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 9 = 0 or x + 8 = 0

Solve

2 x - 9 = 0 : x = \frac{9}{2}

Solve

x + 8 = 0 : x = - 8

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = - 8

x, x^{2} + y^{2} - 2 y - z^{2} = 0

- 2 x^{2} + 2 x - 5 = 0

2 x = x^{2} - 4 x

4 x^{2} + 27 x - 7 = 0

x^{2} + 2 x - 25 = 0

What are the solutions to the equation (2x-9)(x+8)=0 ?
The solutions to the equation (2x-9)(x+8)=0 are x= 9/2 ,x=-8
Find the zeros of (2x-9)(x+8)=0
The zeros of (2x-9)(x+8)=0 are x= 9/2 ,x=-8