What are the solutions to the equation 2x=x^2-4x ?

The solutions to the equation 2x=x^2-4x are x=6,x=0

Find the zeros of 2x=x^2-4x

The zeros of 2x=x^2-4x are x=6,x=0

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2 x = x^{2} - 4 x

x = 6, x = 0

Solution steps

2 x = x^{2} - 4 x

Switch sides

x^{2} - 4 x = 2 x

Move

2 x

to the left side

x^{2} - 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 0 = 6

x_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 1}

x = \frac{- ( - 6 ) + 6}{2 \cdot 1} : 6

x = \frac{- ( - 6 ) - 6}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 6, x = 0

4 x^{2} + 27 x - 7 = 0

x^{2} + 2 x - 25 = 0

z^{2} + 3 z + 2 = 0

19 + c^{2} = 10

7 x^{2} - 13 x = 14

What are the solutions to the equation 2x=x^2-4x ?
The solutions to the equation 2x=x^2-4x are x=6,x=0
Find the zeros of 2x=x^2-4x
The zeros of 2x=x^2-4x are x=6,x=0