What are the solutions to the equation y^2+16y+4=44 ?

The solutions to the equation y^2+16y+4=44 are y=2(sqrt(26)-4),y=-2(4+sqrt(26))

Find the zeros of y^2+16y+4=44

The zeros of y^2+16y+4=44 are y=2(sqrt(26)-4),y=-2(4+sqrt(26))

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y^{2} + 16 y + 4 = 44

y = 2 (26 - 4), y = - 2 (4 + 26)

Decimal Notation

y = 2.19803 \dots, y = - 18.19803 \dots

Solution steps

y^{2} + 16 y + 4 = 44

Move

44

to the left side

y^{2} + 16 y - 40 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 40) = 426

y_{1, 2} = \frac{- 16 \pm 4 26}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 16 + 4 26}{2 \cdot 1}, y_{2} = \frac{- 16 - 4 26}{2 \cdot 1}

y = \frac{- 16 + 4 26}{2 \cdot 1} : 2 (26 - 4)

y = \frac{- 16 - 4 26}{2 \cdot 1} : - 2 (4 + 26)

The solutions to the quadratic equation are:

y = 2 (26 - 4), y = - 2 (4 + 26)

2 x (x - 3) = 5

x^{2} + 1 0^{2} = 1 2^{2}

- 4 x^{2} + 8 x = 0

7 x^{2} - 9 x = 0

y^{2} - 14 y

What are the solutions to the equation y^2+16y+4=44 ?
The solutions to the equation y^2+16y+4=44 are y=2(sqrt(26)-4),y=-2(4+sqrt(26))
Find the zeros of y^2+16y+4=44
The zeros of y^2+16y+4=44 are y=2(sqrt(26)-4),y=-2(4+sqrt(26))