What are the solutions to the equation 100-x^2=52+2x ?

The solutions to the equation 100-x^2=52+2x are x=-8,x=6

Find the zeros of 100-x^2=52+2x

The zeros of 100-x^2=52+2x are x=-8,x=6

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100 - x^{2} = 52 + 2 x

x = - 8, x = 6

Solution steps

100 - x^{2} = 52 + 2 x

Move

2 x

to the left side

100 - x^{2} - 2 x = 52

Move

52

to the left side

- x^{2} - 2 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 48}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 48 = 14

x_{1, 2} = \frac{- ( - 2 ) \pm 14}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 14}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 14}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 14}{2 ( - 1 )} : - 8

x = \frac{- ( - 2 ) - 14}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = - 8, x = 6

x^{2} - 4 x - 72 = 0

x^{2} = \frac{x + 3}{2}

a^{2} = a 5

x, 2 x^{2} + 2 y^{2} + 4 x + 2 y + 10 = 0

3 x^{2} - 6 x = 0

What are the solutions to the equation 100-x^2=52+2x ?
The solutions to the equation 100-x^2=52+2x are x=-8,x=6
Find the zeros of 100-x^2=52+2x
The zeros of 100-x^2=52+2x are x=-8,x=6