What are the solutions to the equation x^2-90x+200=0 ?

The solutions to the equation x^2-90x+200=0 are x=5(9+sqrt(73)),x=5(9-sqrt(73))

Find the zeros of x^2-90x+200=0

The zeros of x^2-90x+200=0 are x=5(9+sqrt(73)),x=5(9-sqrt(73))

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x^{2} - 90 x + 200 = 0

x = 5 (9 + 73), x = 5 (9 - 73)

Decimal Notation

x = 87.72001 \dots, x = 2.27998 \dots

Solution steps

x^{2} - 90 x + 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 90 ) \pm ( - 90 ) ^{2} - 4 \cdot 1 \cdot 200}{2 \cdot 1}

(- 90)^{2} - 4 \cdot 1 \cdot 200 = 1073

x_{1, 2} = \frac{- ( - 90 ) \pm 10 73}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 90 ) + 10 73}{2 \cdot 1}, x_{2} = \frac{- ( - 90 ) - 10 73}{2 \cdot 1}

x = \frac{- ( - 90 ) + 10 73}{2 \cdot 1} : 5 (9 + 73)

x = \frac{- ( - 90 ) - 10 73}{2 \cdot 1} : 5 (9 - 73)

The solutions to the quadratic equation are:

x = 5 (9 + 73), x = 5 (9 - 73)

\frac{3}{2} x^{2} - 4 x - 1 = 0

x^{2} + 12 = 4 x

- 4 x^{2} - 2 x + 2 = 0

a x^{2} - a x + 8 = 0

x^{2} - 1 x - 3.75 = 0

What are the solutions to the equation x^2-90x+200=0 ?
The solutions to the equation x^2-90x+200=0 are x=5(9+sqrt(73)),x=5(9-sqrt(73))
Find the zeros of x^2-90x+200=0
The zeros of x^2-90x+200=0 are x=5(9+sqrt(73)),x=5(9-sqrt(73))