What are the solutions to the equation -4x^2-2x+2=0 ?

The solutions to the equation -4x^2-2x+2=0 are x=-1,x= 1/2

Find the zeros of -4x^2-2x+2=0

The zeros of -4x^2-2x+2=0 are x=-1,x= 1/2

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- 4 x^{2} - 2 x + 2 = 0

x = - 1, x = \frac{1}{2}

Decimal Notation

x = - 1, x = 0.5

Solution steps

- 4 x^{2} - 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 4 ) \cdot 2}{2 ( - 4 )}

(- 2)^{2} - 4 (- 4) \cdot 2 = 6

x_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6}{2 ( - 4 )}, x_{2} = \frac{- ( - 2 ) - 6}{2 ( - 4 )}

x = \frac{- ( - 2 ) + 6}{2 ( - 4 )} : - 1

x = \frac{- ( - 2 ) - 6}{2 ( - 4 )} : \frac{1}{2}

The solutions to the quadratic equation are:

x = - 1, x = \frac{1}{2}

a x^{2} - a x + 8 = 0

x^{2} - 1 x - 3.75 = 0

x^{2} + 4 x + 10

2 x (x - 5) = 0

3 (x + 5)^{2} - 12 x = 6 x + 138

What are the solutions to the equation -4x^2-2x+2=0 ?
The solutions to the equation -4x^2-2x+2=0 are x=-1,x= 1/2
Find the zeros of -4x^2-2x+2=0
The zeros of -4x^2-2x+2=0 are x=-1,x= 1/2