What are the solutions to the equation 20x^2-9x=20 ?

The solutions to the equation 20x^2-9x=20 are x= 5/4 ,x=-4/5

Find the zeros of 20x^2-9x=20

The zeros of 20x^2-9x=20 are x= 5/4 ,x=-4/5

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20 x^{2} - 9 x = 20

x = \frac{5}{4}, x = - \frac{4}{5}

Decimal Notation

x = 1.25, x = - 0.8

Solution steps

20 x^{2} - 9 x = 20

Move

20

to the left side

20 x^{2} - 9 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 20 ( - 20 )}{2 \cdot 20}

(- 9)^{2} - 4 \cdot 20 (- 20) = 41

x_{1, 2} = \frac{- ( - 9 ) \pm 41}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 41}{2 \cdot 20}, x_{2} = \frac{- ( - 9 ) - 41}{2 \cdot 20}

x = \frac{- ( - 9 ) + 41}{2 \cdot 20} : \frac{5}{4}

x = \frac{- ( - 9 ) - 41}{2 \cdot 20} : - \frac{4}{5}

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = - \frac{4}{5}

5 n^{2} - 20 n + 6 = 0

x, x^{2} - y^{3} = 0

s^{2} + 8 s + 20 = 0

2500 = - 0.5 x^{2} + 40 x - 300

x, (x + y)^{2} = 1

What are the solutions to the equation 20x^2-9x=20 ?
The solutions to the equation 20x^2-9x=20 are x= 5/4 ,x=-4/5
Find the zeros of 20x^2-9x=20
The zeros of 20x^2-9x=20 are x= 5/4 ,x=-4/5