What are the solutions to the equation (x+1)^2=56 ?

The solutions to the equation (x+1)^2=56 are x=2sqrt(14)-1,x=-2sqrt(14)-1

Find the zeros of (x+1)^2=56

The zeros of (x+1)^2=56 are x=2sqrt(14)-1,x=-2sqrt(14)-1

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(x + 1)^{2} = 56

x = 214 - 1, x = - 214 - 1

Decimal Notation

x = 6.48331 \dots, x = - 8.48331 \dots

Solution steps

(x + 1)^{2} = 56

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 56 : x = 214 - 1

Solve

x + 1 = - 56 : x = - 214 - 1

The solutions to the quadratic equation are:

x = 214 - 1, x = - 214 - 1

y^{2} - 6 y - 15 = 0

3 x^{2} - 42 x = - 120

x^{2} - 2 x - 19 = 0

x^{2} + x^{2} = 4

2 x^{2} - x - 3 = 0

What are the solutions to the equation (x+1)^2=56 ?
The solutions to the equation (x+1)^2=56 are x=2sqrt(14)-1,x=-2sqrt(14)-1
Find the zeros of (x+1)^2=56
The zeros of (x+1)^2=56 are x=2sqrt(14)-1,x=-2sqrt(14)-1