What are the solutions to the equation x^2-52x=42.24 ?

The solutions to the equation x^2-52x=42.24 are x= 264/5 ,x=-4/5

Find the zeros of x^2-52x=42.24

The zeros of x^2-52x=42.24 are x= 264/5 ,x=-4/5

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x^{2} - 52 x = 42.24

x = \frac{264}{5}, x = - \frac{4}{5}

Decimal Notation

x = 52.8, x = - 0.8

Solution steps

x^{2} - 52 x = 42.24

Multiply both sides by

100

100 x^{2} - 5200 x = 4224

Move

4224

to the left side

100 x^{2} - 5200 x - 4224 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5200 ) \pm ( - 5200 ) ^{2} - 4 \cdot 100 ( - 4224 )}{2 \cdot 100}

(- 5200)^{2} - 4 \cdot 100 (- 4224) = 5360

x_{1, 2} = \frac{- ( - 5200 ) \pm 5360}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- ( - 5200 ) + 5360}{2 \cdot 100}, x_{2} = \frac{- ( - 5200 ) - 5360}{2 \cdot 100}

x = \frac{- ( - 5200 ) + 5360}{2 \cdot 100} : \frac{264}{5}

x = \frac{- ( - 5200 ) - 5360}{2 \cdot 100} : - \frac{4}{5}

The solutions to the quadratic equation are:

x = \frac{264}{5}, x = - \frac{4}{5}

(5 x - 6)^{2} - 1 = 15

2 x^{2} = - 12 x + 4

x^{2} + 4 = - 12 x

y, x = 1 - y^{2}

a^{2} + a

What are the solutions to the equation x^2-52x=42.24 ?
The solutions to the equation x^2-52x=42.24 are x= 264/5 ,x=-4/5
Find the zeros of x^2-52x=42.24
The zeros of x^2-52x=42.24 are x= 264/5 ,x=-4/5