What are the solutions to the equation -x^2+6x+8=0 ?

The solutions to the equation -x^2+6x+8=0 are x=3-sqrt(17),x=3+sqrt(17)

Find the zeros of -x^2+6x+8=0

The zeros of -x^2+6x+8=0 are x=3-sqrt(17),x=3+sqrt(17)

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- x^{2} + 6 x + 8 = 0

x = 3 - 17, x = 3 + 17

Decimal Notation

x = - 1.12310 \dots, x = 7.12310 \dots

Solution steps

- x^{2} + 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) \cdot 8}{2 ( - 1 )}

6^{2} - 4 (- 1) \cdot 8 = 217

x_{1, 2} = \frac{- 6 \pm 2 17}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 17}{2 ( - 1 )}, x_{2} = \frac{- 6 - 2 17}{2 ( - 1 )}

x = \frac{- 6 + 2 17}{2 ( - 1 )} : 3 - 17

x = \frac{- 6 - 2 17}{2 ( - 1 )} : 3 + 17

The solutions to the quadratic equation are:

x = 3 - 17, x = 3 + 17

x^{2} - 12 x - 9 = 0

y^{2} - 2 y + 3 = 0

2 X^{2} - 5 X - 3 = 0

2 x^{2} - 5 x - 42 = 0

\frac{1}{6} t^{2} - 25 = 0

What are the solutions to the equation -x^2+6x+8=0 ?
The solutions to the equation -x^2+6x+8=0 are x=3-sqrt(17),x=3+sqrt(17)
Find the zeros of -x^2+6x+8=0
The zeros of -x^2+6x+8=0 are x=3-sqrt(17),x=3+sqrt(17)