What are the solutions to the equation ax^2-bx=0 ?

The solutions to the equation ax^2-bx=0 are x= b/a ,x=0;\quad a\ne 0

Find the zeros of ax^2-bx=0

The zeros of ax^2-bx=0 are x= b/a ,x=0;\quad a\ne 0

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a x^{2} - b x = 0

x = \frac{b}{a}, x = 0; a \neq = 0

Solution steps

a x^{2} - b x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - b ) \pm ( - b ) ^{2} - 4 a \cdot 0}{2 a}

Simplify

(- b)^{2} - 4 a \cdot 0 : b

x_{1, 2} = \frac{- ( - b ) \pm b}{2 a}; a \neq = 0

Separate the solutions

x_{1} = \frac{- ( - b ) + b}{2 a}, x_{2} = \frac{- ( - b ) - b}{2 a}

x = \frac{- ( - b ) + b}{2 a} : \frac{b}{a}

x = \frac{- ( - b ) - b}{2 a} : 0

The solutions to the quadratic equation are:

x = \frac{b}{a}, x = 0; a \neq = 0

4 x^{2} - 6 x + 7 = 0

x, 2 x^{2} + 2 x y + 2 y^{2} - 2 x - 10 y + 11 = 0

2 x (x - 3) = - 5

2 x (x - 3) = 10

n^{2} + 8^{2} = 1 2^{2}

What are the solutions to the equation ax^2-bx=0 ?
The solutions to the equation ax^2-bx=0 are x= b/a ,x=0;\quad a\ne 0
Find the zeros of ax^2-bx=0
The zeros of ax^2-bx=0 are x= b/a ,x=0;\quad a\ne 0