What are the solutions to the equation 4x^2+96=-40x ?

The solutions to the equation 4x^2+96=-40x are x=-4,x=-6

Find the zeros of 4x^2+96=-40x

The zeros of 4x^2+96=-40x are x=-4,x=-6

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4 x^{2} + 96 = - 40 x

x = - 4, x = - 6

Solution steps

4 x^{2} + 96 = - 40 x

Move

40 x

to the left side

4 x^{2} + 96 + 40 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 40 x + 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 4 \cdot 96}{2 \cdot 4}

4 0^{2} - 4 \cdot 4 \cdot 96 = 8

x_{1, 2} = \frac{- 40 \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 40 + 8}{2 \cdot 4}, x_{2} = \frac{- 40 - 8}{2 \cdot 4}

x = \frac{- 40 + 8}{2 \cdot 4} : - 4

x = \frac{- 40 - 8}{2 \cdot 4} : - 6

The solutions to the quadratic equation are:

x = - 4, x = - 6

3 x^{2} - 6 x - 1 = 0

0 = - x^{2} + 2 x + 8

9 x^{2} - 12 x + 4 = 4

4 x^{2} + b x - 27 = 0

- 7 x + 15 = 4 x^{2}

What are the solutions to the equation 4x^2+96=-40x ?
The solutions to the equation 4x^2+96=-40x are x=-4,x=-6
Find the zeros of 4x^2+96=-40x
The zeros of 4x^2+96=-40x are x=-4,x=-6