What are the solutions to the equation x^2+ax+10=0 ?

The solutions to the equation x^2+ax+10=0 are x=(-a+sqrt(a^2-40))/2 ,x=(-a-sqrt(a^2-40))/2

Find the zeros of x^2+ax+10=0

The zeros of x^2+ax+10=0 are x=(-a+sqrt(a^2-40))/2 ,x=(-a-sqrt(a^2-40))/2

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x^{2} + a x + 10 = 0

x = \frac{- a + a ^{2} - 40}{2}, x = \frac{- a - a ^{2} - 40}{2}

Solution steps

x^{2} + a x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- a \pm a ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

a^{2} - 4 \cdot 1 \cdot 10 : a^{2} - 40

x_{1, 2} = \frac{- a \pm a ^{2} - 40}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- a + a ^{2} - 40}{2 \cdot 1}, x_{2} = \frac{- a - a ^{2} - 40}{2 \cdot 1}

x = \frac{- a + a ^{2} - 40}{2 \cdot 1} : \frac{- a + a ^{2} - 40}{2}

x = \frac{- a - a ^{2} - 40}{2 \cdot 1} : \frac{- a - a ^{2} - 40}{2}

The solutions to the quadratic equation are:

x = \frac{- a + a ^{2} - 40}{2}, x = \frac{- a - a ^{2} - 40}{2}

b, a^{2} = b^{2} + c^{2}

0 = x^{2} + 8 x + 15

s^{2} - 0.1 s + 1 = 0

x^{2} + 8 x + 16 = 1

x, f = \frac{5}{3} m^{4} x^{2} - 7 m^{3} x - 3 m

What are the solutions to the equation x^2+ax+10=0 ?
The solutions to the equation x^2+ax+10=0 are x=(-a+sqrt(a^2-40))/2 ,x=(-a-sqrt(a^2-40))/2
Find the zeros of x^2+ax+10=0
The zeros of x^2+ax+10=0 are x=(-a+sqrt(a^2-40))/2 ,x=(-a-sqrt(a^2-40))/2