What are the solutions to the equation 0=x^2+8x+15 ?

The solutions to the equation 0=x^2+8x+15 are x=-3,x=-5

Find the zeros of 0=x^2+8x+15

The zeros of 0=x^2+8x+15 are x=-3,x=-5

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0 = x^{2} + 8 x + 15

x = - 3, x = - 5

Solution steps

0 = x^{2} + 8 x + 15

Switch sides

x^{2} + 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 15 = 2

x_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2}{2 \cdot 1}, x_{2} = \frac{- 8 - 2}{2 \cdot 1}

x = \frac{- 8 + 2}{2 \cdot 1} : - 3

x = \frac{- 8 - 2}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 3, x = - 5

s^{2} - 0.1 s + 1 = 0

x^{2} + 8 x + 16 = 1

x, f = \frac{5}{3} m^{4} x^{2} - 7 m^{3} x - 3 m

u^{2} - 7 u - 18 = 0

x^{2} + 3 x = x + 7

What are the solutions to the equation 0=x^2+8x+15 ?
The solutions to the equation 0=x^2+8x+15 are x=-3,x=-5
Find the zeros of 0=x^2+8x+15
The zeros of 0=x^2+8x+15 are x=-3,x=-5