What are the solutions to the equation (3x-4)(x-2)-5=0 ?

The solutions to the equation (3x-4)(x-2)-5=0 are x=3,x= 1/3

Find the zeros of (3x-4)(x-2)-5=0

The zeros of (3x-4)(x-2)-5=0 are x=3,x= 1/3

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(3 x - 4) (x - 2) - 5 = 0

x = 3, x = \frac{1}{3}

Decimal Notation

x = 3, x = 0.33333 \dots

Solution steps

(3 x - 4) (x - 2) - 5 = 0

Expand

(3 x - 4) (x - 2) - 5 : 3 x^{2} - 10 x + 3

3 x^{2} - 10 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

(- 10)^{2} - 4 \cdot 3 \cdot 3 = 8

x_{1, 2} = \frac{- ( - 10 ) \pm 8}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 8}{2 \cdot 3}, x_{2} = \frac{- ( - 10 ) - 8}{2 \cdot 3}

x = \frac{- ( - 10 ) + 8}{2 \cdot 3} : 3

x = \frac{- ( - 10 ) - 8}{2 \cdot 3} : \frac{1}{3}

The solutions to the quadratic equation are:

x = 3, x = \frac{1}{3}

3 x^{2} + 7 x - 12 = - 2 x

3 - 8 v - 5 v^{2} = 2 v

x^{2} = \frac{81}{144}

- 4 x^{2} = 6 x

x^{2} + 6 x - 20 = 0

What are the solutions to the equation (3x-4)(x-2)-5=0 ?
The solutions to the equation (3x-4)(x-2)-5=0 are x=3,x= 1/3
Find the zeros of (3x-4)(x-2)-5=0
The zeros of (3x-4)(x-2)-5=0 are x=3,x= 1/3