What are the solutions to the equation x^2+6x-20=0 ?

The solutions to the equation x^2+6x-20=0 are x=-3+sqrt(29),x=-3-sqrt(29)

Find the zeros of x^2+6x-20=0

The zeros of x^2+6x-20=0 are x=-3+sqrt(29),x=-3-sqrt(29)

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x^{2} + 6 x - 20 = 0

x = - 3 + 29, x = - 3 - 29

Decimal Notation

x = 2.38516 \dots, x = - 8.38516 \dots

Solution steps

x^{2} + 6 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 20) = 229

x_{1, 2} = \frac{- 6 \pm 2 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 29}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 29}{2 \cdot 1}

x = \frac{- 6 + 2 29}{2 \cdot 1} : - 3 + 29

x = \frac{- 6 - 2 29}{2 \cdot 1} : - 3 - 29

The solutions to the quadratic equation are:

x = - 3 + 29, x = - 3 - 29

- 3 x^{2} + 17 x - 20 = 0

x, x^{2} + y^{2} + 1 = 0

x^{2} - 8 x - 10 = 0

x (x + 2) + 5 = 3 (2 - x) + x - 4

x^{2} = 2^{2} + 1^{2}

What are the solutions to the equation x^2+6x-20=0 ?
The solutions to the equation x^2+6x-20=0 are x=-3+sqrt(29),x=-3-sqrt(29)
Find the zeros of x^2+6x-20=0
The zeros of x^2+6x-20=0 are x=-3+sqrt(29),x=-3-sqrt(29)