What are the solutions to the equation -3x^2+17x-20=0 ?

The solutions to the equation -3x^2+17x-20=0 are x= 5/3 ,x=4

Find the zeros of -3x^2+17x-20=0

The zeros of -3x^2+17x-20=0 are x= 5/3 ,x=4

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- 3 x^{2} + 17 x - 20 = 0

x = \frac{5}{3}, x = 4

Decimal Notation

x = 1.66666 \dots, x = 4

Solution steps

- 3 x^{2} + 17 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 ( - 3 ) ( - 20 )}{2 ( - 3 )}

1 7^{2} - 4 (- 3) (- 20) = 7

x_{1, 2} = \frac{- 17 \pm 7}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 17 + 7}{2 ( - 3 )}, x_{2} = \frac{- 17 - 7}{2 ( - 3 )}

x = \frac{- 17 + 7}{2 ( - 3 )} : \frac{5}{3}

x = \frac{- 17 - 7}{2 ( - 3 )} : 4

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = 4

x, x^{2} + y^{2} + 1 = 0

x^{2} - 8 x - 10 = 0

x (x + 2) + 5 = 3 (2 - x) + x - 4

x^{2} = 2^{2} + 1^{2}

3 x^{2} = - 54 x - 231

What are the solutions to the equation -3x^2+17x-20=0 ?
The solutions to the equation -3x^2+17x-20=0 are x= 5/3 ,x=4
Find the zeros of -3x^2+17x-20=0
The zeros of -3x^2+17x-20=0 are x= 5/3 ,x=4