What are the solutions to the equation a^2+10a+18=9 ?

The solutions to the equation a^2+10a+18=9 are a=-1,a=-9

Find the zeros of a^2+10a+18=9

The zeros of a^2+10a+18=9 are a=-1,a=-9

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a^{2} + 10 a + 18 = 9

a = - 1, a = - 9

Solution steps

a^{2} + 10 a + 18 = 9

Move

9

to the left side

a^{2} + 10 a + 9 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 9 = 8

a_{1, 2} = \frac{- 10 \pm 8}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 10 + 8}{2 \cdot 1}, a_{2} = \frac{- 10 - 8}{2 \cdot 1}

a = \frac{- 10 + 8}{2 \cdot 1} : - 1

a = \frac{- 10 - 8}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

a = - 1, a = - 9

x^{2} - 2 = - x

x^{2} - (3 a + 2 b) x + 6 ab = 0

x^{2} - 8 x + 16 = 49

5 x^{2} - 10 x - 35 = 0

x^{2} - 28 = - 3 x

What are the solutions to the equation a^2+10a+18=9 ?
The solutions to the equation a^2+10a+18=9 are a=-1,a=-9
Find the zeros of a^2+10a+18=9
The zeros of a^2+10a+18=9 are a=-1,a=-9