What are the solutions to the equation k^2+2k-35=0 ?

The solutions to the equation k^2+2k-35=0 are k=5,k=-7

Find the zeros of k^2+2k-35=0

The zeros of k^2+2k-35=0 are k=5,k=-7

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k^{2} + 2 k - 35 = 0

k = 5, k = - 7

Solution steps

k^{2} + 2 k - 35 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 35) = 12

k_{1, 2} = \frac{- 2 \pm 12}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 2 + 12}{2 \cdot 1}, k_{2} = \frac{- 2 - 12}{2 \cdot 1}

k = \frac{- 2 + 12}{2 \cdot 1} : 5

k = \frac{- 2 - 12}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

k = 5, k = - 7

x, 9 x^{2} - y^{2} - 36 x - 6 y + 27 = 0

4 x^{2} - 400 = 0

7^{2} + y^{2} = 2 5^{2}

(3 x - 1) (x + 2) - x (x - 4) = 0

40 = y^{2}

What are the solutions to the equation k^2+2k-35=0 ?
The solutions to the equation k^2+2k-35=0 are k=5,k=-7
Find the zeros of k^2+2k-35=0
The zeros of k^2+2k-35=0 are k=5,k=-7