What are the solutions to the equation v^2+v-30=0 ?

The solutions to the equation v^2+v-30=0 are v=5,v=-6

Find the zeros of v^2+v-30=0

The zeros of v^2+v-30=0 are v=5,v=-6

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v^{2} + v - 30 = 0

v = 5, v = - 6

Solution steps

v^{2} + v - 30 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 30) = 11

v_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 1 + 11}{2 \cdot 1}, v_{2} = \frac{- 1 - 11}{2 \cdot 1}

v = \frac{- 1 + 11}{2 \cdot 1} : 5

v = \frac{- 1 - 11}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

v = 5, v = - 6

\frac{5 !}{2 ! 3 !} (\frac{6}{7})^{2} (\frac{5}{7})^{3}

- 4 x^{2} - 8 x - 4 = 0

\frac{- 66 + 27 i}{- 6 - 3 i}

k (4 k + 1) = 0

16 p + 37 = 49 - 21 p

What are the solutions to the equation v^2+v-30=0 ?
The solutions to the equation v^2+v-30=0 are v=5,v=-6
Find the zeros of v^2+v-30=0
The zeros of v^2+v-30=0 are v=5,v=-6