What are the solutions to the equation 0=2x^2-10x+8 ?

The solutions to the equation 0=2x^2-10x+8 are x=4,x=1

Find the zeros of 0=2x^2-10x+8

The zeros of 0=2x^2-10x+8 are x=4,x=1

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0 = 2 x^{2} - 10 x + 8

x = 4, x = 1

Solution steps

0 = 2 x^{2} - 10 x + 8

Switch sides

2 x^{2} - 10 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 \cdot 8 = 6

x_{1, 2} = \frac{- ( - 10 ) \pm 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 6}{2 \cdot 2}, x_{2} = \frac{- ( - 10 ) - 6}{2 \cdot 2}

x = \frac{- ( - 10 ) + 6}{2 \cdot 2} : 4

x = \frac{- ( - 10 ) - 6}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = 4, x = 1

5 x^{2} = - 30 x - 65

x^{2} + 4 x - 25 = 0

- 3 t^{2} + 14 t - 14 = 0

9 b^{2} = 25

12 x^{2} - 13 x - 4 = 0

What are the solutions to the equation 0=2x^2-10x+8 ?
The solutions to the equation 0=2x^2-10x+8 are x=4,x=1
Find the zeros of 0=2x^2-10x+8
The zeros of 0=2x^2-10x+8 are x=4,x=1