What are the solutions to the equation solvefor y,x^2+y^2=64 ?

The solutions to the equation solvefor y,x^2+y^2=64 are y=sqrt(64-x^2),y=-sqrt(64-x^2)

Find the zeros of solvefor y,x^2+y^2=64

The zeros of solvefor y,x^2+y^2=64 are y=sqrt(64-x^2),y=-sqrt(64-x^2)

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solve for

y, x^{2} + y^{2} = 64

y = 64 - x^{2}, y = - 64 - x^{2}

Solution steps

x^{2} + y^{2} = 64

Move

x^{2}

to the right side

y^{2} = 64 - x^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 64 - x^{2}, y = - 64 - x^{2}

\frac{x - 3 ( x - 1 )}{2} = \frac{( x - 1 ) ^{2}}{2}

0 = x^{2} + 6 x + 10

6 x^{2} - 9 x + 1 = x

2 (x - 9)^{2} + 8 = 0

x, x^{2} y = 1

What are the solutions to the equation solvefor y,x^2+y^2=64 ?
The solutions to the equation solvefor y,x^2+y^2=64 are y=sqrt(64-x^2),y=-sqrt(64-x^2)
Find the zeros of solvefor y,x^2+y^2=64
The zeros of solvefor y,x^2+y^2=64 are y=sqrt(64-x^2),y=-sqrt(64-x^2)