What are the solutions to the equation solvefor x,x^2+2x+5=0 ?

The solutions to the equation solvefor x,x^2+2x+5=0 are x=-1+2i,x=-1-2i

Find the zeros of solvefor x,x^2+2x+5=0

The zeros of solvefor x,x^2+2x+5=0 are x=-1+2i,x=-1-2i

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x, x^{2} + 2 x + 5 = 0

x = - 1 + 2 i, x = - 1 - 2 i

Solution steps

x^{2} + 2 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 5 : 4 i

x_{1, 2} = \frac{- 2 \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 4 i}{2 \cdot 1}

x = \frac{- 2 + 4 i}{2 \cdot 1} : - 1 + 2 i

x = \frac{- 2 - 4 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

x = - 1 + 2 i, x = - 1 - 2 i

b, A = \frac{1}{2} h (b^{1} + b^{2})

2 x^{2} - 8 x - 8 = 0

x^{2} - 8 x + 12 = 0

8.65 = \frac{x ^{2} \cdot 4 π \cdot 4}{1.18 \cdot 344 \cdot 2}

2 x^{2} - (a + 6) x + 3 a = 0

What are the solutions to the equation solvefor x,x^2+2x+5=0 ?
The solutions to the equation solvefor x,x^2+2x+5=0 are x=-1+2i,x=-1-2i
Find the zeros of solvefor x,x^2+2x+5=0
The zeros of solvefor x,x^2+2x+5=0 are x=-1+2i,x=-1-2i