What are the solutions to the equation completesquare x^2-8x+12=0 ?

The solutions to the equation completesquare x^2-8x+12=0 are x=6,x=2

Find the zeros of completesquare x^2-8x+12=0

The zeros of completesquare x^2-8x+12=0 are x=6,x=2

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x^{2} - 8 x + 12 = 0

x = 6, x = 2

Solution steps

x^{2} - 8 x + 12 = 0

Move

12

to the right side

x^{2} - 8 x = - 12

Rewrite in the form

(x + a)^{2} = b

(x - 4)^{2} = 4

For

the solutions are

f (x) = a, - a

Solve

x - 4 = 4 : x = 6

Solve

x - 4 = - 4 : x = 2

The solutions to the quadratic equation are:

x = 6, x = 2

8.65 = \frac{x ^{2} \cdot 4 π \cdot 4}{1.18 \cdot 344 \cdot 2}

2 x^{2} - (a + 6) x + 3 a = 0

9 x^{2} - 7 x - 9 = 0

x^{2} - x + 7

x^{2} - x + 9

What are the solutions to the equation completesquare x^2-8x+12=0 ?
The solutions to the equation completesquare x^2-8x+12=0 are x=6,x=2
Find the zeros of completesquare x^2-8x+12=0
The zeros of completesquare x^2-8x+12=0 are x=6,x=2