What are the solutions to the equation 4x^2-11x+30=16 ?

The solutions to the equation 4x^2-11x+30=16 are x= 11/8+i(sqrt(103))/8 ,x= 11/8-i(sqrt(103))/8

Find the zeros of 4x^2-11x+30=16

The zeros of 4x^2-11x+30=16 are x= 11/8+i(sqrt(103))/8 ,x= 11/8-i(sqrt(103))/8

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4 x^{2} - 11 x + 30 = 16

x = \frac{11}{8} + i \frac{103}{8}, x = \frac{11}{8} - i \frac{103}{8}

Solution steps

4 x^{2} - 11 x + 30 = 16

Move

16

to the left side

4 x^{2} - 11 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 4 \cdot 14}{2 \cdot 4}

Simplify

(- 11)^{2} - 4 \cdot 4 \cdot 14 : 103 i

x_{1, 2} = \frac{- ( - 11 ) \pm 103 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 103 i}{2 \cdot 4}, x_{2} = \frac{- ( - 11 ) - 103 i}{2 \cdot 4}

x = \frac{- ( - 11 ) + 103 i}{2 \cdot 4} : \frac{11}{8} + i \frac{103}{8}

x = \frac{- ( - 11 ) - 103 i}{2 \cdot 4} : \frac{11}{8} - i \frac{103}{8}

The solutions to the quadratic equation are:

x = \frac{11}{8} + i \frac{103}{8}, x = \frac{11}{8} - i \frac{103}{8}

x^{2} + x = - 3

x, f = (3 m - 1) x^{2} - m x + m

20 x^{2} + 3920 = 0

x^{2} - 10 x - 50 = 0

7 (x - 4)^{2} - 3 (x + 5) = 4 (x + 1) (x - 1) - 2

What are the solutions to the equation 4x^2-11x+30=16 ?
The solutions to the equation 4x^2-11x+30=16 are x= 11/8+i(sqrt(103))/8 ,x= 11/8-i(sqrt(103))/8
Find the zeros of 4x^2-11x+30=16
The zeros of 4x^2-11x+30=16 are x= 11/8+i(sqrt(103))/8 ,x= 11/8-i(sqrt(103))/8