What are the solutions to the equation x^2+3=6x ?

The solutions to the equation x^2+3=6x are x=3+sqrt(6),x=3-sqrt(6)

Find the zeros of x^2+3=6x

The zeros of x^2+3=6x are x=3+sqrt(6),x=3-sqrt(6)

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x^{2} + 3 = 6 x

x = 3 + 6, x = 3 - 6

Decimal Notation

x = 5.44948 \dots, x = 0.55051 \dots

Solution steps

x^{2} + 3 = 6 x

Move

6 x

to the left side

x^{2} + 3 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 3 = 26

x_{1, 2} = \frac{- ( - 6 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 6}{2 \cdot 1} : 3 + 6

x = \frac{- ( - 6 ) - 2 6}{2 \cdot 1} : 3 - 6

The solutions to the quadratic equation are:

x = 3 + 6, x = 3 - 6

3 x^{2} + 42 x = - 24

9 - x^{2} = x^{2} + 1

7 x^{2} - 9 x + 12 = 5 x^{2} - 6

1 2^{2} = 6^{2} + x^{2}

r^{2} - 10 = 3 r

What are the solutions to the equation x^2+3=6x ?
The solutions to the equation x^2+3=6x are x=3+sqrt(6),x=3-sqrt(6)
Find the zeros of x^2+3=6x
The zeros of x^2+3=6x are x=3+sqrt(6),x=3-sqrt(6)