What are the solutions to the equation 6x^2+2x+3=0 ?

The solutions to the equation 6x^2+2x+3=0 are x=-1/6+i(sqrt(17))/6 ,x=-1/6-i(sqrt(17))/6

Find the zeros of 6x^2+2x+3=0

The zeros of 6x^2+2x+3=0 are x=-1/6+i(sqrt(17))/6 ,x=-1/6-i(sqrt(17))/6

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6 x^{2} + 2 x + 3 = 0

x = - \frac{1}{6} + i \frac{17}{6}, x = - \frac{1}{6} - i \frac{17}{6}

Solution steps

6 x^{2} + 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 6 \cdot 3}{2 \cdot 6}

Simplify

2^{2} - 4 \cdot 6 \cdot 3 : 217 i

x_{1, 2} = \frac{- 2 \pm 2 17 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 2 + 2 17 i}{2 \cdot 6}, x_{2} = \frac{- 2 - 2 17 i}{2 \cdot 6}

x = \frac{- 2 + 2 17 i}{2 \cdot 6} : - \frac{1}{6} + i \frac{17}{6}

x = \frac{- 2 - 2 17 i}{2 \cdot 6} : - \frac{1}{6} - i \frac{17}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{6} + i \frac{17}{6}, x = - \frac{1}{6} - i \frac{17}{6}

3 x^{2} + 5 = 41

x, x^{2} - x = 0

6 x^{2} + 2 x + 6 = 0

x^{2} - 12 x + 11 = 0

25 \cdot 1 0^{- 9} s^{2} + 0.35 \cdot 1 0^{- 3} s + 1 = 0

What are the solutions to the equation 6x^2+2x+3=0 ?
The solutions to the equation 6x^2+2x+3=0 are x=-1/6+i(sqrt(17))/6 ,x=-1/6-i(sqrt(17))/6
Find the zeros of 6x^2+2x+3=0
The zeros of 6x^2+2x+3=0 are x=-1/6+i(sqrt(17))/6 ,x=-1/6-i(sqrt(17))/6