What are the solutions to the equation x^2-3x+5=3-x ?

The solutions to the equation x^2-3x+5=3-x are x=1+i,x=1-i

Find the zeros of x^2-3x+5=3-x

The zeros of x^2-3x+5=3-x are x=1+i,x=1-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 3 x + 5 = 3 - x

x = 1 + i, x = 1 - i

Solution steps

x^{2} - 3 x + 5 = 3 - x

Move

x

to the left side

x^{2} - 2 x + 5 = 3

Move

3

to the left side

x^{2} - 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 2 : 2 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 i}{2 \cdot 1} : 1 + i

x = \frac{- ( - 2 ) - 2 i}{2 \cdot 1} : 1 - i

The solutions to the quadratic equation are:

x = 1 + i, x = 1 - i

x^{2} + 10 = 3 x - 3

(x + 5) (x + 3) = 0

2 4^{2} + 3 2^{2} = c^{2}

2 x^{2} - 9 x - 32 = 0

- x^{2} = x^{2}

What are the solutions to the equation x^2-3x+5=3-x ?
The solutions to the equation x^2-3x+5=3-x are x=1+i,x=1-i
Find the zeros of x^2-3x+5=3-x
The zeros of x^2-3x+5=3-x are x=1+i,x=1-i