What are the solutions to the equation -6x^2-3=0 ?

The solutions to the equation -6x^2-3=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i

Find the zeros of -6x^2-3=0

The zeros of -6x^2-3=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i

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- 6 x^{2} - 3 = 0

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

- 6 x^{2} - 3 = 0

Move

3

to the right side

- 6 x^{2} = 3

Divide both sides by

- 6

x^{2} = - \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{2}, x = - - \frac{1}{2}

- \frac{1}{2} = \frac{1}{2} i

- - \frac{1}{2} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

x^{2} + 4 x + 17 = 0

5 x^{2} + 10 x - 20 = 0

b^{2} = 49

c^{2} - 16 c + 64 = 0

2 x^{2} + 16 x - 70 = - 4

What are the solutions to the equation -6x^2-3=0 ?
The solutions to the equation -6x^2-3=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i
Find the zeros of -6x^2-3=0
The zeros of -6x^2-3=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i